Answer:
32.7%
Explanation:
Given:
Power output P_(out) = 600MW
We know that
Power input P_(in)= energy/time=(4.8 x 10^6 kg x 3.3 x 10^7 J/kg) /( 24 x 3600)=1,833 MW
Efficiency =(P_out÷P_in) x 100% = (600÷1833)×100%
Efficiency = 32.7%
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