Question

Please help me out with this :)

Answer 1

C = 0 is the minimum value

Explanation:

Sketch

2x + y = 20

with x- intercept = (10, 0) and y- intercept = (0, 20)

2x + 3y = 36

with x- intercept = (18, 0) and y- intercept = (0, 12)

Solve 2x + y = 20 and 2x + 3y = 36 to find intercept at (6, 8)

The feasible region has vertices at

(0, 20), (12, 0) and (6, 8)

Evaluate the objective function C = x + y at each vertex

(0, 20) → C = 0 + 20 = 20

(12, 0) → C = 12 + 0 = 12 ← minimum value

(6, 8) → C = 6 + 8 = 14

The minimum value is C = 12 when x = 12 and y = 0

Answer 2

c=0

Explanation:

*graphed*

coordinates are 0,0 6,8 0,12 10,0

*plug them into c=x+y*

C=0+0=0

C=6+8=14

C=0+12=12

C=10+0=10

since 0 is the smallest value C=o and if they want a fr number then your second option is C=10