Answer:
![(x^2+5x+6)/(x+2)](https://img.qammunity.org/2020/formulas/mathematics/high-school/u3ykjw09c43ltugarowglvm0yi58job6tp.png)
⇒
![x+3](https://img.qammunity.org/2020/formulas/mathematics/high-school/woj0rrjm61nev51989rvtudftjl44fz43c.png)
Explanation:
To simplify:
![(x^2+5x+6)/(x+2)](https://img.qammunity.org/2020/formulas/mathematics/high-school/u3ykjw09c43ltugarowglvm0yi58job6tp.png)
To simplify the given expression we need to factor the numerator.
We have
![x^2+5x+6](https://img.qammunity.org/2020/formulas/mathematics/middle-school/wsac725dd6b6hqafq8l05rs9pf0khhswul.png)
Using split the middle term method by splitting
into two terms
and
such that
and
![ax(bx)=6x^2](https://img.qammunity.org/2020/formulas/mathematics/high-school/a8ymcoyxt6bwazphvgpgujfn5c8a0xr4tb.png)
We see that [
and
]
Thus we can write
⇒
![x^2+2x+3x+6](https://img.qammunity.org/2020/formulas/mathematics/high-school/x2o18liwaai5jvma5d54g0q6la225jiwi4.png)
Factoring in pairs by taking the GCF of terms in pairs.
⇒
![x(x+2)+3(x+2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ov1unsw9asg7a47cdg5gk5wwg872mhop9u.png)
Factoring the whole expression as
is a common factor.
⇒
![(x+2)(x+3)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/rippi6k84w5ye2tmitnobwz3l5qt2dbabx.png)
Now, the expression can be rewritten as:
Canceling out the common expressions, we have.
⇒
![x+3](https://img.qammunity.org/2020/formulas/mathematics/high-school/woj0rrjm61nev51989rvtudftjl44fz43c.png)