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Find the exact distance between the line 6x-y=3 and the point (6,2). Show your work. Explain your answer.

User Dregad
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2 Answers

1 vote

Answer:

Using the distance formula, you can solve to show that the distance between 6x-y= 3 = 37/ sqrt 37, or sqrt 37

Explanation:

User John Deev
by
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2 votes

Answer:

The distance of point ( 6 , 2 ) from line 6 x - y = 3 is
(31)/(√(37) ) unit .

Explanation:

Given as :

The equation of line is 6 x - y = 3

And The points is ( 6 , 2 )

Let The distance between the line and points is d unit

So, The distance of point from the line =
\frac{\begin{vmatrix}ax & +b y & + c\end{vmatrix}}{\sqrt{a^(2)+b^(2)}}

Or, d =
\frac{\begin{vmatrix}6* x & +(-1)*  y & + (-3)\end{vmatrix}}{\sqrt{6^(2)+(-1)^(2)}}

Or, d =
\frac{\begin{vmatrix}6* 6 & +(-1)*  2 & + (-3)\end{vmatrix}}{\sqrt{6^(2)+(-1)^(2)}}

Or, d =
(36 - 2 - 3)/(√(37) )

d =
(31)/(√(37) ) unit

Hence The distance of point ( 6 , 2 ) from line 6 x - y = 3 is
(31)/(√(37) ) unit . Answer

User Zac Kwan
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8.3k points

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