Answer:
Drew saves a distance of
by taking the shortcut.
Explanation:
Here is an image of the routes.
We have drawn it assigning the signs NSEW where N=North,S=South ,E=East and W=West.
Now the total distance covered by Drew = OA+AB+BC
![=(1.25+0.75+0.25)=2.25\ miles](https://img.qammunity.org/2020/formulas/mathematics/middle-school/xuhmsykm5c04nyq2n3vjlepmzuotcstazh.png)
We see by joining C with O it has a shortcut.
And it forms a right angled triangle.
,
at D.
By using Pythagoras theorem we can find the shortcut distance.
OC is the hypotenuse and
![OC=√(1^2+0.75^2) = 1.25\ miles](https://img.qammunity.org/2020/formulas/mathematics/middle-school/b8yf6gjkbopqgf5oy36fers728mzbkgbac.png)
So Drew saves
of distance following the advice of his friend and opting for the shortcut route.