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Syringe initially holds a sample of gas with a volume of 285 mL at 355 K and 1.88 atm. To what temperature must the gas in the syringe be heated/cooled in order to have a volume of 435 mL at 2.50 atm

User DJDJ
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1 Answer

5 votes

Answer:

720.535 K

Step-by-step explanation:

Concept tested: Combined gas law

From the question we are given;

  • Initial volume, V1 of the gas is 285 mL
  • Initial pressure, P1 of the gas is 1.88 atm
  • Initial temperature, T1 of gas is 355 K
  • Final pressure of the gas, P2 = 2.50 atm
  • Final volume of the gas, V2 = 435 mL

We are required to calculate the new temperature, T2of the gas;

  • To solve the question we are going to use the combined gas law.
  • According to the combined gas law;


(P1V1)/(T1)=(P2V2)/(T2)

  • Rearranging the formula we can calculate the new temperature;


T2=(P2V2T1)/(P1V1)

  • Therefore;


T2=((2.50atm)(435mL)(355K))/((1.88atm)(285mL))


T2=720.535K

Therefore, the new temperature of the gas in the syringe must be 720.535 K

User Rkt
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8.0k points
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