Question

What is the distance between the p&ints (8, 3) and (8, - 6) ?

O
3 units
O
8 units
O
9 units
o
17 units

Answer 1

`\displaystyle 9\:units`

Explanation:

Use the Distance Formula:

`\displaystyle √([-x_1 + x_2]^2 + [-y_1 + y_2]^2) = D \\ \\ √([-8 + 8]^2 + [-3 - 6]^2) = √(0^2 + [-9]^2) = √(0 + 81) = √(81) = 9`

Since we are talking about distance, we ONLY want the NON-NEGATIVE root.

I am joyous to assist you anytime.

Answer 2

Using distance formula:

`d = \sqrt{(8 - 8 {)}^(2) + ( - 6 - 3) {}^(2) } = 9`

Answer: 9 units