Answer:
The answer is:
As x decreases without bound, the graph of f(x) approaches y = 0
As x increases without bound, the graph of f(x) increases without bound
Explanation:
When x goes -∞;
![\lim_(x \to -\infty) f(x) =5^(x-1)=0](https://img.qammunity.org/2020/formulas/mathematics/high-school/qxagxygk92juj2nz2ygri2c12fazv15nag.png)
When x goes to ∞;
![\lim_(x \to \infty) f(x)=5^(x-1)= \infty](https://img.qammunity.org/2020/formulas/mathematics/high-school/1mw6pqflsqm1acprh1uhvkez02qple4wej.png)
Therefore the solution is;
As x decreases without bound, the graph of f(x) approaches y = 0
As x increases without bound, the graph of f(x) increases without bound