219k views
4 votes
The function f(x)=5^(x−1) is shown on the coordinate plane.

Select from the drop-down menus to correctly describe the end behavior of ​

f(x)


As x decreases without bound, the graph of

f(x)


A. approaches y = 0

B. increases without bound

C. decreases without bound


As x increases without bound, the graph of

f(x)


A. approaches y = 0

B. increases without bound

C. decreases without bound

The function f(x)=5^(x−1) is shown on the coordinate plane. Select from the drop-down-example-1
User Tsilavina
by
7.9k points

2 Answers

3 votes

Just from the figure,

As x decreases, y approaches 0

As x increases, y increases without bound

User Zenab
by
7.9k points
6 votes

Answer:

The answer is:

As x decreases without bound, the graph of f(x) approaches y = 0

As x increases without bound, the graph of f(x) increases without bound

Explanation:

When x goes -∞;


\lim_(x \to -\infty) f(x) =5^(x-1)=0

When x goes to ∞;


\lim_(x \to \infty) f(x)=5^(x-1)= \infty

Therefore the solution is;

As x decreases without bound, the graph of f(x) approaches y = 0

As x increases without bound, the graph of f(x) increases without bound

User Namila
by
8.3k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories