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The function f(x)=5^(x−1) is shown on the coordinate plane.

Select from the drop-down menus to correctly describe the end behavior of ​

f(x)


As x decreases without bound, the graph of

f(x)


A. approaches y = 0

B. increases without bound

C. decreases without bound


As x increases without bound, the graph of

f(x)


A. approaches y = 0

B. increases without bound

C. decreases without bound

The function f(x)=5^(x−1) is shown on the coordinate plane. Select from the drop-down-example-1
User Tsilavina
by
5.8k points

2 Answers

3 votes

Just from the figure,

As x decreases, y approaches 0

As x increases, y increases without bound

User Zenab
by
5.3k points
6 votes

Answer:

The answer is:

As x decreases without bound, the graph of f(x) approaches y = 0

As x increases without bound, the graph of f(x) increases without bound

Explanation:

When x goes -∞;


\lim_(x \to -\infty) f(x) =5^(x-1)=0

When x goes to ∞;


\lim_(x \to \infty) f(x)=5^(x-1)= \infty

Therefore the solution is;

As x decreases without bound, the graph of f(x) approaches y = 0

As x increases without bound, the graph of f(x) increases without bound

User Namila
by
4.9k points