Question

6) At elevated temperatures, methylisonitrile (CH3NC) isomerizes to acetonitrile (CH3CN):CH3NC (g)  CH3CN (g)At the start of an experiment, there are 0.200 mol of reactant and 0 mol of product in the reaction vessel.After 25 min, 0.108 mol of reactant (CH3NC) remain. There are mol of product (CH3CN) in thereaction vessel.A) 0.200 B) 0.540 C) 0.022 D) 0.092 E) 0.308

Answer 1

Answer: The moles of product present in the vessel is 0.092 moles

Step-by-step explanation:

For the given chemical equation:

`CH_3CN(g)\rightleftharpoons CH_3CN(g)`

We are given:

Initial moles of reactant = 0.200 moles

Unreacted moles of reactant = 0.108 moles

Reacted moles of reactant = 0.200 - 0.108 = 0.092 moles

By Stoichiometry of the reaction:

1 mole of reactant produces 1 mole of product

So, 0.092 moles of reactant will produce =
`\frac{1}[1}* 0.092=0.092mol` of product

Hence, the moles of product present in the vessel is 0.092 moles