Question

What is the area of trapezoid ABCD ?

Enter your answer as a decimal or whole number in the box. Do not round at any steps.

units²

Answer 1

Explanation:

The answer is correct, I am taking the test and It is 37.5 units ^2

Answer 2

The area of the trapezoid ABCD = 37.5 sq. units.

Explanation:

If we join points B and D on the figure given with the question.

Then area of the trapezoid ABCD = area of Δ ABD + area of Δ BDC

Now, area of Δ ABD =
`(1)/(2) |- 3(5 - (- 2)) + 1(- 2 - 2) + 0(2 - 5)| = 12.5` sq, units.

Again area of Δ BDC =
`(1)/(2) |1(- 2 -(- 3)) +0(- 3 - 5)+ 7(5 - (- 2))|` = 25 sq, units

Therefore, the area of the trapezoid ABCD = 12.5 + 25 = 37.5 sq. units.

We know the formula of area of a triangle having vertices
`(x_(1), y_(1))`,
`(x_(2), y_(2))`, and
`(x_(3), y_(3))` will be equal to

Δ =
`(1)/(2) |x_(1) (y_(2) - y_(3))+ x_(2) (y_(3) - y_(1)) + x_(3) (y_(1) - y_(2)) |` (Answer)