Question

Use the following table of a school bus during morning pickups to calculate its average speed between 0h and 2.34 h. ​

Answer 1

6.983 km/hr

Step-by-step explanation:

This problem asks for the the average rate of change, which is Δy/Δx. In this case, the time represents x, and the position represents y. The average rate of change is (16.34 - 0.0)/(2.34 - 0.000) ≈ 6.983 km/hr

Answer 2

Answer : The average speed of between 0 hr and 2.34 hr is, 9.820 km/hr

Explanation :

Average speed : It is defined as the ratio total distance to total time.

Formula used :

`\text{Average speed}=\frac{\text{Total distance}}{\text{Total time}}`

Now put all the given values in the above formula, we get:

`\text{Average speed}=\frac{\text{Total distance}}{\text{Total time}}`

`\text{Average speed}=((0.0+1.2+2.8+4.2+16.34)km)/((0.000+0.024+0.051+0.084+2.34)hr)`

`\text{Average speed}=(24.54km)/(2.499hr)`

`\text{Average speed}=9.820km/hr`

Therefore, the average speed of between 0 hr and 2.34 hr is, 9.820 km/hr