Question

A small sphere of mass 2 kg is attached to the end of a cord of length 2 m and rotated in a vertical circle about a fixed point O. Determine the tension in the cord at the uppermost point of the trajectory if the speed at this point is 8 m/s. Use g=9.8 m/s2. Report your answer as a positive number in newtons.

Answer 1

tension in the string at the top position of the ball will be given as

T = 44.4 N

Step-by-step explanation:

At the top position of the trajectory we have force equation given as

`T + mg = (mv^2)/(R)`

here we have

`T = (mv^2)/(R) - mg`

so we have

`T = (2(8^2))/(2) - (2 * 9.8)`

`T = 64 - 19.6`

`T = 44.4 N`

So tension in the string at the top position of the ball will be given as

T = 44.4 N