Answer:
(a)The length of DA = 3.2 units (app.)
(b) The length of CD = 6.32 units
(c)Area of the rectangle = 20.2 sq units.
Explanation:
Here the coordinates of the rectangle are given as
A(-3,0), B(3,2), C(4,-1) and D(-2,-3).
DISTANCE FORMULA: For two points P(a,b) and Q(c,d)
The length of PQ =
![√((c-a)^2 + (d-b)^2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/s3jrnafd12cbm0od5uhnyiuidt8dqtqwu3.png)
(a)The length of DA =
![√((-3-0)^2+ (-2-(-3))^2) = √((-3)^2+ (1)^2) \\= √(9+ 1) = √(10) = 3.16](https://img.qammunity.org/2020/formulas/mathematics/middle-school/1o87urmmaa1l13up67f25mnyppemesmoqf.png)
Hence, the length of DA = 3.2 units (app.)
(b) The length of CD =
![√((-2-4)^2+ (-3-(-1))^2) = √((-6)^2+ (-2)^2) \\= √(36+ 4) = √(40) = 7.28](https://img.qammunity.org/2020/formulas/mathematics/middle-school/bhpxh8ddo5f3bhe2iijhldppnexi5e4jrn.png)
Hence, the length of CD = 6.32 units
(c)Now, area of the rectangle = LENGTH X WIDTH
= Length of DA x Length of CD
= 3.2 units x 6.32 units = 20.2 sq units.