Question

The positions of the digits of a certain two-digit number are swapped. The difference between the original two-digit number and the new two-digit number is 54. The ones digit of the original number is 3 more than twice the tens digit. What is the original two-digit number?

Answer 1

Explanation:

let the digit at unit place be x

and digit at ten's place be y

then number=10y+x

when the digits are swapped number=10x+y

also x =2y+3

so 10x+y-(10y+x)=54

10 x+y-10 y-x=54

9x-9y=54

x-y=6

2y+3-y=6

y=3

x=2*3+3=9

number=10×9+3=93