1 Answer

Kerryann · Answer 1 · 2020-07-14T12:36:59+0000

For this case we have the following system of equations:

$6x-y = 4\\y = 4x + 2$

Substituting the second equation into the first we have:

$6x- (4x + 2) = 4\\6x-4x-2 = 4\\2x = 4 + 2\\2x = 6\\x = \frac {6} {2}\\x = 3$

We find the value of the variable "y":

$y = 4x + 2\\y = 4 (3) +2\\y = 12 + 2\\y = 14$

Finally, the system solution is:

(x, y) :( 3,14)

Answer:

The value of "x" in the system solution is 3.

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