Question

Through (-1,3) parallel to y= 5/4x+3

Answer 1

The equation of line with slope
`(5)/(4)` and points ( - 1 , 3 ) is y =
`(5)/(4)` x +
`(17)/(4)`

Explanation:

Given equation of a line as :

y =
`(5)/(4)` x + 3

The line equation is in the form of y = m x + c

Where m is the slope of the line

Now while comparing given line equation with standard line equation ,

So , slope of the line m =
`(5)/(4)`

∵ Another line is passing through points ( - 1 , 3 ) , and is parallel to given line

Now if two lines are parallel then slope of both lines are equal

Let The slope of another line = M

So, M = m =
`(5)/(4)`

∴ The equation of line with slope
`(5)/(4)` and passing through points ( - 1 , 3 ) is

y -
`y_1` = M × ( x -
`x_1` )

Or, y - 3 = ×
`(5)/(4)` ( x + 1 )

or, 4 × ( y - 3 ) = 5 × ( x + 1 )

Or, 4 y - 12 = 5 x + 5

Or, 4 y = 5 x + 17

∴ y =
`(5)/(4)` x +
`(17)/(4)`

Hence The equation of line with slope
`(5)/(4)` and points ( - 1 , 3 ) is y =
`(5)/(4)` x +
`(17)/(4)` Answer