Answer:
Shawn's kinetic energy is 61.45 J.
Step-by-step explanation:
Given;
Mass of the system is,
![m=52.3\ kg](https://img.qammunity.org/2020/formulas/physics/middle-school/2bkr8ksjhe3z361iplzfri1va3wmqeodvo.png)
Displacement of the bike is,
![d=1.6\ km=1.6* 1000=1600\ m](https://img.qammunity.org/2020/formulas/physics/middle-school/t2cussqh285gfgjbotn7bjoi8zlvupmenj.png)
Time taken is,
![t=17.4\ min=17.4* 60=1044\ s](https://img.qammunity.org/2020/formulas/physics/middle-school/375itcpbl3i7r0jjn3e8ewlfhpa3zb1jg1.png)
Let the constant velocity be
.
For constant velocity, magnitude of velocity is given as distance by time.
Therefore,
![v=(d)/(t)=(1600)/(1044)=1.533\ m/s](https://img.qammunity.org/2020/formulas/physics/middle-school/53ig7hhmzy52aqfl7kgn6fp4x86wkbvxa9.png)
Now, kinetic energy of a body is given as:
![KE=(1)/(2)mv^2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/qm3oiu3t5knkt2lzxpgz8n1rhs06ibh22e.png)
Here,
![m=52.3\ kg,\ v=1.533\ m/s](https://img.qammunity.org/2020/formulas/physics/middle-school/nd4q5grz6vo2joeyv5xhto5agmd71a4ho9.png)
![\therefore KE=(1)/(2)* 52.3* (1.533)^2\\KE=0.5* 52.3* 2.35\\KE=61.45\ J](https://img.qammunity.org/2020/formulas/physics/middle-school/wc8k7mhjwd4525qtcs30rm4go0gbho53sr.png)
Therefore, Shawn's kinetic energy is 61.45 J.