Stoichiometry is “quantitative relationship” among the “reactants” and the “products” in a “chemical reaction”.
Step-by-step explanation:
In stoichiometry “stoicheion” means element and “metron” means measure in Greek. The stoichiometric calculation depends upon “stoichiometric coefficients” in a “chemical equation” which can be explained as the “number of moles” of each substance (reactants or products). Stoichiometric calculation is done as follows:
For example reaction between nitrogen and hydrogen to form ammonia as
![\mathrm{N}_(2)(\mathrm{g})+3 \mathrm{H}_(2)(\mathrm{g}) \longrightarrow 2 \mathrm{NH}_(3)(\mathrm{g})](https://img.qammunity.org/2020/formulas/chemistry/college/l66w88bbl343cwxx6buxlfigyxtq9whtn7.png)
Here stoichiometric coefficients show that “one molecule of nitrogen” reacts with “three molecules of hydrogen” to form “two molecules of ammonia”. Multiplying Avogadro number
to no of molecules in equation:
![\text { For } \mathrm{N}_(2): 1 * 6.022 * 10^(23)=1 \mathrm{mol}](https://img.qammunity.org/2020/formulas/chemistry/college/7xoew2lnmsgv49e4e6wqjt219uk8kns2xv.png)
![\text { For } 2 \mathrm{NH}_(3): 2 * 6.022 * 10^(23)=2 \mathrm{mol}](https://img.qammunity.org/2020/formulas/chemistry/college/yr613xtks33gy1xujknqlt8xy7nllxrpfk.png)
Taking molar masses into consideration:
![\text { For } \mathrm{N}_(2): 1 * 28.0=28.0 \mathrm{gm}](https://img.qammunity.org/2020/formulas/chemistry/college/cmwp9h1xhon1hykr36csp249fxnf6n2o46.png)
![\text { For } 3 \mathrm{H}_(2): 3 * 2=6.0 \mathrm{gm}](https://img.qammunity.org/2020/formulas/chemistry/college/l2e3me3xrec9a1mqcvgw8pzqnzuhub5r0x.png)
![\text { For } 2 \mathrm{NH}_(3): 2 * 17=34 \mathrm{gm}](https://img.qammunity.org/2020/formulas/chemistry/college/tul6e7krxsfpsq4nogm6hw7isfpj50f1wq.png)
Hence balanced equation gives stoichiometric coefficients which gives proportion by moles.