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Line p goes through (6,12) and has a slope of 5/2 please write in slope-intercept form

User KJDII
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2 Answers

2 votes

Answer:

y=5/2x-3

Explanation:

y-y1=m(x-x1)

y-12=5/2(x-6)

y=5/2x-30/2+12

y=5/2x-15+12

y=5/2x-3

User Jheel Agrawal
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8.0k points
2 votes

Answer:

The equation of line P with slope
(5)/(2) and points ( 6 , 12 ) is y =
(5)/(2) x - 3 .

Explanation:

Given as :

The slope of the line P is
(5)/(2)

The line P passes through point ( 6 , 12 )

Now, Equation of line in slope intercept form can be written as :


y-y_1 = m( x - x_1)

Or, y-12 =
(5)/(2) ( x - 6)

Or , y - 12 =
(5)/(2) x -
(5)/(2) × 6

O y - 12 =
(5)/(2) x - 15

Or, y =
(5)/(2) x - 15 + 12

∴ y =
(5)/(2) x - 3

Hence The equation of line P with slope
(5)/(2) and points ( 6 , 12 ) is y =
(5)/(2) x - 3 . Answer

User Sumit Munot
by
8.7k points