Question

The scores of the athletes are 32,45,33,22,50,48. Find the variance.

Answer 1

Explanation:

First, find the mean ; (32+45+33+22+50+48) / 6 = 230/6

Mean = 38.33

Variance =
`(SUM(X-meanX)^(2) )/(n-1)`

n = sample size

Variance =
`((32-38.33)^(2) +(45-38.33)^(2)+(33-38.33)^(2) +(22-38.33)^(2)+(50-38.33)^(2)+(48-38.33)^(2) )/(5)`

Variance =
`((44.4889 +40.0689 +28.4089 + 266.6689 +136.1889 +93.5089))/(5)`

=
`(609.3334)/(5)`

= 121.8667

Therefore, variance = 121.87