Question

Equation for the line containing (4,5) and (-2,-4)

Answer 1

Explanation:

first need to find the slope

-4-5=-9

-2-4=-6

=3/2

y-5=3/2(x-4) this is your point slope equation

y-5=3/2x-6

y=3/2x-1 this is your slope intercept equation

-3/2x+y=-1

muliply by -2

3x-2y=2 this is your equation in standard form

Answer 2

Answer:2y - 3x = -2

Explanation:

The equation of line in two point form is given as :

`(y-y_(1))/(x -x_(1))` =
`(y_(2)-y_(1))/(x_(2)-x_(1))`

from the question,

`x_(1)` = 4

`x_(2)` = -2

`y_(1)` = 5

`y_(2)` = - 4

substituting into the formula , we have

`(-4-5)/(-2-4)` =
`(y-5)/(x-4)`

`(9)/(6)` =
`(y-5)/(x-4)`

`(3)/(2)` =
`(y-5)/(x-4)`

cross multiplying , we have

2(y-5) = 3(x-4)

2y - 10 = 3x - 12

2y - 3x = -12 +10

2y - 3x = -2