Question

For what values of x does the graph of f(x) have a vertical asymptote? f(x)=3/x²+x-2

a. 1, -2
b. 3, 0
c. 3, -2
d. -1, 2

Answer 1

a. 1, -2

Explanation:

`f(x)=(3)/(x^(2)+x-2)\\f(x)=(3)/((x+2)(x-1))\\`

Find when the denominator equates to 0.

x+2 = 0

x = -2

x-1 = 0

x = 1

Set restrictions for x in the denominator to find the vertical asymptotes

x ≠ -2, 1