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A 50kg football player heading to the right at 2.5 m/s

collides with and tackles a 40kg player heading left at 3.5
m/s toward him. What is the speed and direction of the
tangled players?

1 Answer

3 votes

Answer:

The speed of the tangled players is
0.17\ ms^(-1) in left direction

Step-by-step explanation:

Mass of Player 1 =
m_1 =
50\ kg

Mass of Player 2 =
m_2 =
40\ kg

Velocity of Player 1 moving right =
v_1=2.5\ ms^(-1)

Velocity of Player 2 moving left =
v_2=-3.5\ ms^(-1)

By law of conservation of momentum:


m_1v_1+m_2v_2=(m_1+m_2)v

Here
v represents the velocity of tangled players.

Plugging in values in the equation.


(50*2.5)+(40*(-3.5))=(50+40)v\\125-140=90v\\-15=90v\\

Dividing both sides by 90.


(-15)/(90)=(90v)/(90)\\-0.167=v


v=0.167\approx 0.17\ ms^(-1)

The negative velocity indicates that the tangled players move to the left after collision.

The speed of the tangled players is
0.17\ ms^(-1) in left direction

User Fixnum
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