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Suppose there were 4,065,014 births in a given year. Of those births 2,081,287 were boys and 1,983,727 were girls. What is the probability that both children will be boys?

User Ennabah
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1 Answer

5 votes

Answer:

The required probability is
\simeq 0.26214

Explanation:

There were 4,065,014 births in a given year and of those births 2,081,287 were boys and 1.983,727 were girls.

So, P(both children will be boys) =
\frac {^(2081287){C}_2}{^(4065014){C}_(2)}


\simeq 0.26214

User Delfuego
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