Question

How many grams of FeCl 3 are in 250. mL of a 0.100 M solution?

O A. 64.9 g
OB. 4.06 g
AI O C 0.0250 g
D. 25.0 g
HAT
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Answer 1

The correct answer is option B

Step-by-step explanation:

`$Molarity=(Weight)/(Molecular \,weight) (1000)/(V(in \, ml))`

Given values,

Molarity of
`$FeCl_3=0.100M$`

Volume of solution,
`$V=250ml$`

Molecular weight of
`$FeCl_3=162.2$`

Substituting this values in Molarity formula, we get

`$0.1=(weight)/(162.2) *(1000)/(250) $\\$\Rightarrow 16.22=weight*4$\\$\Rightarrow weight=(16.22)/(4) $\\$\therefore weight=4.06g$`