Answer:
There is no
value, as there is no solution.
Explanation:
Given:
The equations are:
![2x+y=1\\4x+2y=-2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/795ag9nulhfm8r8hi9xfermeip2eqn5ce0.png)
Divide the 2nd equation by 2. This gives,
![(4x)/(2)+(2y)/(2)=(-2)/(2)\\2x+y=-1](https://img.qammunity.org/2020/formulas/mathematics/middle-school/is628nen5zjikxbieggxemy6kuyp7i4pcp.png)
Now, subtract equation 1 and 2.
![2x+y-2x-y=1-(-1)\\2x-2x+y-y=1+1\\0=2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/cq5nck13bgdl77cula61qzq2d0cg82fq37.png)
We are getting 0 equal to 2 which is not possible as 0 is less than 2. So, there is no solution for this pair of equations.