Question

Answer for i^372
And i^527 with explanation please

Answer 1

`i {}^(372) = 1 \\ i {}^(527 ) = - i`

Explanation:

Greetings !

Note that:-

`i {}^(2n) = 1</u></strong><strong><u>.</u></strong><strong><u>\: if \: n \: is \: even \\ \: \: \: \: \: \: \: = - 1</u></strong><strong><u>.</u></strong><strong><u> \: if \: n \: is \: odd`

And also

`i {}^(2n + 1) = </strong><strong>i</strong><strong>.</strong><strong> \: if \: n \: is \: even \\ \: \: \: \: \: \: \: \: \: \: = - </strong><strong>i</strong><strong>.</strong><strong>\: if \: n \: is \: dd`

Thus, remembering these general formula plug in values in the place of n and solve.

Therefore,

`i {}^(2(186)) = i {}^(372) = 1`

where n is even thus its 1 from the above explanation

`i {}^(2(263) + 1) = i {}^(527) = - i`

following the same procedure the values exceeds to be -i.

Hope it helps !!!