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Evaluate the limit as x goes to infinity of x^3e^-x/5

User Aurril
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1 Answer

5 votes

Answer: 0

Explanation:


(x^(3)e^(-x))/(5)

This could be written as


(x^(3) )/(5e^(-x) )

Applying L'H rule and differentiating 3 times , we have


(6)/(5e^(x) )

taking the limit as x goes to infinity , we have

0

User Cheruvian
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