Question

Kevin is 3 years older than Daniel. Two years ago, Kevin was 4 times as old as Daniel.

Let k be Kevin's age and let d be Daniel's age.

Which system of equations represents this situation?


a. d=k+3

d-2=4(k-2)


b. k=d+3

k-2=4(d-2)


c. d−2=(k−2)+3

d=4k


d. k−2=(d−2)+3

k=4d

​



​

Answer 1

B .As Kelvin(k) is 3 years older than Daniel(d),to make their age equal 3 is added to d in first case and in second case; 2 years ago Kelvin was 4 times as old as Daniel .So,k-2=4(d-2). 2 years is deducted from their present age and for Daniel it is multiplied by 4.