Answer:
The polynomial that represents the area to be finished on the dulcimer shown is
![A=(3)/(2)h^2+h](https://img.qammunity.org/2020/formulas/mathematics/middle-school/k8mpuoblwgf357ypsh0c3m4c9pvar0t85r.png)
Explanation:
Given:
The given figure is a trapezium with opposite parallel to each other.
The opposite parallel sides are given as:
![b_(1)=2h+1\\b_(2)=h+1](https://img.qammunity.org/2020/formulas/mathematics/middle-school/wtqscox6mme006a77zgg2ags4knt7mgk8l.png)
The height of the trapezoid is,
![h=h](https://img.qammunity.org/2020/formulas/mathematics/middle-school/vt8p1snepbgtkggwttqhmg9efyn8hvd1b3.png)
Now, the area of a trapezium is given as:
![A=(1)/(2)(\textrm{Sum of parallel sides)}* (Height)\\A=(1)/(2)(b_(1)+b_(2))* h\\A=(h)/(2)(2h+1+h+1)\\A=(h)/(2)(2h+h +1+1)\\A=(h)/(2)(3h+2)\\A=(3h^2)/(2)+(2h)/(2)\\A=(3)/(2)h^2+h](https://img.qammunity.org/2020/formulas/mathematics/middle-school/2x079kqlq47i2b4ur970vvlmo3wexzh1d8.png)
Therefore, the polynomial that represents the area to be finished on the dulcimer shown is
![A=(3)/(2)h^2+h](https://img.qammunity.org/2020/formulas/mathematics/middle-school/k8mpuoblwgf357ypsh0c3m4c9pvar0t85r.png)