Answer:
There are 0.0211 moles of air in the bottle
Step-by-step explanation:
Step 1: Data given
Temperature of air = 15°C = 273.15 + 15 = 288.15 Kelvin
Standard pressure = 1 atm
Volume of the bottle = 0.500 L
Step 2: ideal gas law
p*V = n*R*T
with p = the pressure of the gas = 1 atm
with V = the volume of the bottle = 0.500 L
with n = the number of moles
with R = the gas constant = 0.08206 L*atm/ mol*K
with T = the temperature of the gas = 15 °C = 288.15 Kelvin
In this case we have:
1atm * 0.500L = n * 0.08206 L*atm/ mol*K * 288.15 K
Number of moles n = (1 atm * 0.500 L)/(0.08206 L*atm/ mol*K * 288.15 K)
Number of moles = 0.0211 moles
There are 0.0211 moles of air in the bottle