Answer:1/(3+x)=(1/3)
1
(1−(−x/3))
1/(3+x)=(1/3)1(1−(−x/3))
Use this fact that
1/(1−t)=
∑
∞
0
t
n
(∗)
1/(1−t)=∑0∞tn (∗)
where
|t|<1
. I mean take
t=−x/3
and...
Note that
|−t|=|t|<1
is the radius of convergence
Explanation:
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