Question

The circuit above has a current of 0.32 A coming out of the power supply. Resistors R1, R2, and R3 have resistances of 408 LaTeX: \OmegaΩ, 2,296 LaTeX: \OmegaΩ, and 3,309 LaTeX: \OmegaΩ respectively, what is the voltage of the power supply

Answer 1

1924 volts

Explanation:

From Ohm's Law:

Voltage (V) = Current (I) x Resistance (R)

V= I R....................................................... (1)

I = 0.32 A

R₁ = 408 Ω

R₂ = 2,296Ω

R₃ = 3,309Ω

Total Resistance = 408 + 2296+3309

= 6,013‬Ω

Substituting into (1), we have :

V= 0.32 x 6,013‬

= 1,924.16‬ volts

≅ 1924 volts