Question

A person lowers a bucket into a well by turning the hand crank, as the drawing illustrates. The crank handle moves with a constant tangential speed of 1.22 m/s on its circular path. The rope holding the bucket unwinds without slipping on the barrel of the crank. Find the linear speed with which the bucket moves down the well.

Answer 1

`v = 0.305 m/s`

Step-by-step explanation:

As we know that diameter of hand crank is given as

`D_1 = 0.4 m`

Also the diameter of the shaft on which the rope is wound is given as

`D_2 = 0.1 m`

now we know that both are moving with same angular speed

so we will have

`(v_1)/(D_1) = (v_2)/(D_2)`

so we will have

`(1.22)/(0.4) = (v)/(0.1)`

`v = 0.305 m/s`