Question

A mathematics exam consists of 10 multiple-choice questions and 5 open-ended problems in which all work must shown. If an examinee must answer 8 of the multiple-choice questions and 3 of the open-ended problems, in how many ways can the questions and problems be chosen?

Answer 1

450 ways

Explanation:

Given that a mathematics exam consists of 10 multiple-choice questions and 5 open-ended problems in which all work must shown.

An examinee must answer 8 of the multiple-choice questions and 3 of the open-ended problems

8 multiple choice questions can be selected from 10 in 10C2 ways and 3 open ended problems in 5/c3 ways

`Total no of ways = 10C8(5C3)\\=45(10)\\450`

In 450 ways the questions and problems can be chosen