Question

When 32.5g of carbon is heated with silicone dioxide, 28.8 g of carbon monoxide is produced. What is the percent yield of carbon monoxide?

Answer 1

Percent yield of carbon monoxide is approximately 38%.

Step-by-step explanation:

Given reaction : C + SiO₂ → Si + CO

On balancing it : 2C + SiO₂ → Si + 2CO

⇒ 2 mole of carbon produces 2 mole of carbon monoxide

or 2×12=24 g of carbon produces 2×(12+16)=56 g of carbon monoxide

⇒ Expected yield of carbon monoxide when 32.5g of carbon is heated with silicon dioxide is 32.5×
`(56)/(24)`

⇒ Expected yield =
`(455)/(6)` = 75.8 g

Actual yield is given as 28.8 g

⇒ The percent yield of carbon monoxide =
`(Actual\ yield)/(Expected\ yield)`×100

=
`(28.8)/(75.8)`×100

≅38%