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A thin metallic spherical shell of radius 41.6 cm has a total charge of 8.55 μC uniformly distributed on it. At the center of the shell is placed a point charge of 4.43 μC . What is the magnitude of the electric field at a distance of 17.9 cm from the center of the spherical shell?

User Penz
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Answer:

E = 1.2443*10⁶ N/C

Step-by-step explanation:

R = 41.6 cm = 0.416 m

Q₁ = 8.55 μC = 8.55*10⁻⁶C

Q₀ = 4.43 μC = 4.43*10⁻⁶C

r = 17.9 cm = 0.179 m

K = 9*10⁹ N*m²/C²

Since r < R we can apply Gauss's Law as follows

E = K*Q₀ / r²

⇒ E = (9*10⁹ N*m²/C²)*(4.43*10⁻⁶C) / (0.179 m)²

⇒ E = 1.2443*10⁶ N/C

User Prakash Kuma
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