146k views
5 votes
Please help!

You need a 15% acid solution for a certain test, but your supplier only ships 5% solution and 17.5% solution. If you need 20 liters of 15% acid solution, how many liters of 5% and 17.5% solution do you need?

User Matt Mower
by
8.7k points

2 Answers

6 votes

Answer:

4 liters of 5% solution and 16 liters of 17.5% solution we need.

Explanation:

Let us assume that x liters of 5% solution and y liters of 17.5% solution are taken.

So, x + y = 20 ........ (1)

As the final solution is of 15%, so we can write

⇒ 5x + 17.5y = 300 ......... (2)

Now, solving equations (1) and (2) we get,

17.5y - 5y = 200

⇒ 12.5y = 200

⇒ y = 16 liters

Hence, x = 20 - y = 4 liters.

Therefore, 4 liters of 5% solution and 16 liters of 17.5% solution we need. (Answer)

User Dmitry Maksimov
by
7.9k points
5 votes

Answer:

4 liters of 5% solution and 16 liters of 17.5% solution we need.

Explanation:

Let us assume that x liters of 5% solution and y liters of 17.5% solution are taken.

So, x + y = 20 ........ (1)

As the final solution is of 15%, so we can write


((5x)/(100)+ (17.5y)/(100))/(x + y) = (15)/(100)

⇒ 5x + 17.5y = 300 ......... (2)

Now, solving equations (1) and (2) we get,

17.5y - 5y = 200

⇒ 12.5y = 200

y = 16 liters

Hence, x = 20 - y = 4 liters.

Therefore, 4 liters of 5% solution and 16 liters of 17.5% solution we need. (Answer)

User BrtH
by
7.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories