Question

Which ion will most likely form a precipitate when reacted with SO42 ?

СІ-
K+
Na+
Ba2+

Answer 1

Ba2+

Step-by-step explanation:

Answer 2

Answer:Ba
`^2+`

Step-by-step explanation:

option A:

`SO_(4)^(2-)` is an anion and
`Cl^(1-)` is also an anion.So,there is no reaction.

option B:

`K^(+)` reacts with
`SO_(4)^(2-)` to form
`K_(2)SO_(4)`.

Since
`K` is a first group element,all its salts are soluble in water.

Hence no precipitate is formed.

option C:

`Na^(+)` reacts with
`SO_(4)^(2-)` to form
`Na_(2)SO_(4)`.

Since
`Na` is a first group element,all its salts are soluble in water.

Hence no precipitate is formed.

option D:

`Ba^(2+)` reacts with
`SO_(4)^(2-)` to form
`BaSO_(4)`.

Solubility of sulphates of second group elements decrease down the group.

So,
`BaSO_(4)` is a precipitate.