For this case we have that by definition, the equation of a line in the slope-intersection form is given by:
![y = mx + b](https://img.qammunity.org/2020/formulas/mathematics/high-school/fc4cgm6covys37zv2opmmp9ps4jxyjepvh.png)
Where:
m: It's the slope
b: It is the cut-off point with the y axis
According to the image, the line goes through the following points:
![(x_ {1}, y_ {1}): (2,1)\\(x_ {2}, y_ {2}): (0,4)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/txfa6yfckvk8q103f8ys320p33ebdtor7a.png)
So, the slope is:
![m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} = \frac {4-1} {0-2} = \frac {3} {- 2} = - \frac {3} {2}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/r88tp6d9z5kdcuv71ep7by54bbxphb2eoo.png)
Thus, the equation is of the form:
![y = - \frac {3} {2} x + b](https://img.qammunity.org/2020/formulas/mathematics/high-school/2l65viknoqiwm4z3fng7kdpc1f1hfu879m.png)
We substitute a point and find "b":
![4 = -\frac {3} {2} (0) + b\\4 = b](https://img.qammunity.org/2020/formulas/mathematics/middle-school/h31w2qzkf4w4moowq5rxgh2ok1rpfgkx7q.png)
Finally, the equation is:
![y = - \frac {3} {2} x + 4](https://img.qammunity.org/2020/formulas/mathematics/high-school/ys8u3yk8f5jixrrcn4yadqx9k28vp8kauk.png)
Answer:
![y = - \frac {3} {2} x + 4](https://img.qammunity.org/2020/formulas/mathematics/high-school/ys8u3yk8f5jixrrcn4yadqx9k28vp8kauk.png)