1 Answer

Don McCurdy · Answer 1 · 2020-02-09T06:08:32+0000

For this case we have that by definition, the equation of the line of the point-slope form is given by:

$y-y_ {0} = m (x-x_ {0})$

Where:

m: Is the slope

$(x_ {0}, y_ {0}):$ is a point that belongs to the line

According to the statement we have the following points:

$(x_ {1}, y_ {1}): (4,5)\\(x_ {2}, y_ {2}): (-3, -1)$

We found the slope:

$m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} = \frac {-1-5} {- 3-4} = \frac {-6} {- 7} = \frac {6} {7}$

Thus, the equation is of the form:

$y-y_ {0} = \frac {6} {7} (x-x_ {0})$

We substitute the point
$(x_ {0}, y_ {0}) :( 4,5)$

$y-5 = \frac {6} {7} (x-4)$

Finally, the point-slope equation is:

$y-5 = \frac {6} {7} (x-4)$

Answer:

$y-5 = \frac {6} {7} (x-4)$

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