Answer:
The null and alternative hypothesis are:
![H_0: \mu\leq27.6\\\\H_1: \mu>27.6](https://img.qammunity.org/2020/formulas/mathematics/college/8zd9k1dtjnolu2fcewn1or0ba80uwowcbn.png)
The null hypothesis can't be rejected.
Explanation:
In this case, we have to perform a hypothesis test of the mean, with known population standard deviation.
The sample has a size of n=210 and the mean of the sample is M=28.0.
The null and alternative hypothesis are:
![H_0: \mu\leq27.6\\\\H_1: \mu>27.6](https://img.qammunity.org/2020/formulas/mathematics/college/8zd9k1dtjnolu2fcewn1or0ba80uwowcbn.png)
The significance level is 0.05.
In this test, if the null hypothesis is rejected, we can claim that the MPG are greater than what the manufacturer says.
The test statistic is:
![z=(M-\mu)/(\sigma)=(28.0-27.6)/(2.3)=(0.4)/(2.3) =0.1739](https://img.qammunity.org/2020/formulas/mathematics/college/go8dlxes5wjuona52cv75idckspzveqpyt.png)
The P-value for z=0.1739 is
.
The P-value is greater than the significance level, so the effect is not significant. The null hypothesis is fail to be rejected.