Question

Find the dimensions of a rectangle given that its perimeter is 80 cm and its length is 1 cm more than twice its width.

Set up your solution using the variables L for the length, W for the width, and P for the perimeter.
Part a: Using the definition of perimeter, write an equation for P in terms of L and W .
Part b: Using the relationship given in the problem statement, write an equation for L in terms of W .
Solve the equations from parts a and b.

Answer 1

The length should equal 27.

The width should equal 13.

A: P= 2L+ 2W

B: L=2W+1

Explanation:

Perimeter is always equal to all of the sides added up.

You can find out the width and length by subsititution.

80=2(2W+1) +2W

80=4W+2+2W

80=6W+2

78=6W

W=13

L=(13*2)+1

L=27