Question

A skier leaves the horizontal end of a ramp with a velocity of 31.0 m/s and lands 156.3 m from the base of a ramp how high is the end of the ramp from the ground ?

Answer 1

The height of ramp = 124.694 m

Step-by-step explanation:

Using second equation of motion,

`s = ut + (1)/(2)at^2`

From the question,

u = 31 m/s; s = 156.3 m, a=0

substituting values

`156.3 = 31* t + 0`

t =
`(156.3)/(31 )`

= 5.042 s

Similary, for the case of landing

t = 5.042 s; initial velocity, u =0

acceleration = acceleration due to gravity, g = 9.81
`m/s^2`

Substituting in
`h = ut + (1)/(2)gt^2`

`h = 0 + (1)/(2) * 9.81 * (5.042)^2`

h = 124.694 m

So height of ramp = 124.694 m