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Two jets leave an air base at the same time and travel in opposite directions. One jet travels 94 mi/h slower than the other. If the two jets are 2956 miles apart after two hours, what is the rate of change?

User ChuckB
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1 Answer

2 votes

Answer:

1478 mi/h

Explanation:

The rate of change is the distance divided by the time.


\text{Rate of change} = \frac{\text{distance}}{\text{time}} = \frac{\text{2956 mi}}{\text{2 h}} = \textbf{1478 mi/h}

User Kota Mori
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