30.7k views
4 votes
How many Solutions does this system have? (1 point)

2x+y=3
6x=9-3y

A)one
B)none
C)infinite
D)two

User Incanus
by
5.2k points

2 Answers

3 votes

Answer:

infinite

Explanation:

User Jhenrique
by
5.6k points
6 votes

The given system of equation that is
2x+y=3 and
6x=9-3y has infinite number of solutions.

Option -C.

Solution:

Need to determine number of solution given system of equation has.


\begin{array}{l}{2 x+y=3} \\\\ {6 x=9-3 y}\end{array}

Let us first bring the equation in standard form for comparison


\begin{array}{l}{2 x+y-3=0} \\\\ {6 x+3 y-9=0}\end{array}


(a_(1))/(a_(2))=(b_(1))/(b_(2)) \\eq (c_(1))/(c_(2))

To check how many solutions are there for system of equations
a_(1) x+b_(1) y+c_(1)=0 \text{ and }a_(2) x+b_(2) y+c_(2)=0, we need to compare ratios of
(a_(1))/(a_(2)), (b_(1))/(b_(2)) \text { and } (c_(1))/(c_(2))

In our case,


a_(1) = 2, b_(1)= 1\text{ and }c_(1)= -3


a_(2)  = 6, b_(2) = 3,\text{ and }c_(2) = -9


\begin{array}{l}{\Rightarrow (a_(1))/(a_(2))=(2)/(6)=(1)/(3)} \\\\ {\Rightarrow (b_(1))/(b_(2))=(1)/(3)} \\\\ {\Rightarrow (c_(1))/(c_(2))=(-3)/(-9)=(1)/(3)} \\\\ {\Rightarrow (a_(1))/(a_(2))=(b_(1))/(b_(2))=(c_(1))/(c_(2))=(1)/(3)}\end{array}

As
(a_(1))/(a_(2))=(b_(1))/(b_(2))=(c_(1))/(c_(2)), so given system of equations have infinite number of solutions.

Hence, we can conclude that system has infinite number of solutions.

User Sendmarsh
by
5.6k points