The given system of equation that is
and
has infinite number of solutions.
Option -C.
Solution:
Need to determine number of solution given system of equation has.
![\begin{array}{l}{2 x+y=3} \\\\ {6 x=9-3 y}\end{array}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/wyvt4cpkkkvqv8h8sn1ybzrqnr8p3tphui.png)
Let us first bring the equation in standard form for comparison
![\begin{array}{l}{2 x+y-3=0} \\\\ {6 x+3 y-9=0}\end{array}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/dm3adrdne0vnm4mdagkn9s1ktylrcdd0ct.png)
![(a_(1))/(a_(2))=(b_(1))/(b_(2)) \\eq (c_(1))/(c_(2))](https://img.qammunity.org/2020/formulas/mathematics/middle-school/clxwp5g1z5drrja2nr2tvpwbfj1po6mzvh.png)
To check how many solutions are there for system of equations
, we need to compare ratios of
![(a_(1))/(a_(2)), (b_(1))/(b_(2)) \text { and } (c_(1))/(c_(2))](https://img.qammunity.org/2020/formulas/mathematics/middle-school/5uoaq1e9v8c4uovm3lj5h19gu7151vidvq.png)
In our case,
![a_(1) = 2, b_(1)= 1\text{ and }c_(1)= -3](https://img.qammunity.org/2020/formulas/mathematics/middle-school/qf1k8e9yce81nm5rd29pek0keddyyz7u4a.png)
![a_(2) = 6, b_(2) = 3,\text{ and }c_(2) = -9](https://img.qammunity.org/2020/formulas/mathematics/middle-school/v2wcflq2ekcpav29uqierf6ffrt2vcb0ad.png)
![\begin{array}{l}{\Rightarrow (a_(1))/(a_(2))=(2)/(6)=(1)/(3)} \\\\ {\Rightarrow (b_(1))/(b_(2))=(1)/(3)} \\\\ {\Rightarrow (c_(1))/(c_(2))=(-3)/(-9)=(1)/(3)} \\\\ {\Rightarrow (a_(1))/(a_(2))=(b_(1))/(b_(2))=(c_(1))/(c_(2))=(1)/(3)}\end{array}](https://img.qammunity.org/2020/formulas/mathematics/middle-school/a84wb5zc2pk0tgu2ec2fhj432bm6tyt4o3.png)
As
, so given system of equations have infinite number of solutions.
Hence, we can conclude that system has infinite number of solutions.