Answer:
The figure below is showing the situation:
Figure
Now let the point is at a distance x from the shoreline where it is making the angle of 45 degrees.
So we have:
x
=
6
tan
θ
Now we have:
d
θ
d
t
=
2
π
5
So we have to find the velocity that is given by:
d
x
d
t
=
d
d
θ
(
6
tan
θ
)
=
6
sec
2
(
θ
)
d
θ
d
t
=>
d
x
d
t
=
6
sec
2
(
π
4
)
2
π
5
is the required velocity
Explanation:
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