Question

A shopper pushes a grocery cart 38.5.0 m at constant speed on level ground, against a 45.9.0 N frictional force. He pushes in a direction 38.0° below the horizontal. What is the work (in J) done on the cart by the shopper?

Answer 1

W=1767.15 J

Step-by-step explanation:

Given that

d= 38.50 m

Fr= 45.9 N

θ = 38.0°

Lets take force applied by shopper = F

Given that he pushed the cart at constant speed it means that acceleration of the system is zero.So the horizontal component of force F should be equal to the friction force.

So the work done by shopper W

W= Fr.d

W= 45.9 x 38.5 J

W=1767.15 J