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Given the sequence is defined by the explicit definition t_n=2^n-nt n = 2 n − n, find the 5th term of the sequence. (ie: t_5t 5)

A. 5

B. 10

C. 27

D. 32

User Azv
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2 Answers

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*100% CORRECT ANSWERS

Given the sequence is defined by the explicit definition t_n=2^n-nt n = 2 n − n, find-example-1
Given the sequence is defined by the explicit definition t_n=2^n-nt n = 2 n − n, find-example-2
Given the sequence is defined by the explicit definition t_n=2^n-nt n = 2 n − n, find-example-3
User Spry Techies
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5.1k points
4 votes

Answer:

If the n-th term of a sequence be , t(n) equal to
2^(n) - n then the 5-th term is 27 but if the n-th term is (2n -n) then the 5-th term is 5.

Step-by-step explanation:

If the n-th term of a sequence be , t(n) =
2^(n) - n

then, the 5-th term is given by, t(5) =
2^(5)- 5

= 32 - 5

= 27

If the n-th term of a sequence be , t(n) = 2n - n = n

then, the 5-th term is given by, t(5) = 5

User Sireini
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